Which of the following is the valid host range for the subnet on which the IP address 192.168.168.188 255.255.255.192 resides?

To understand the valid host range for the subnet that includes the IP address 192.168.168.188 with a subnet mask of 255.255.255.192, we first need to analyze the subnetting involved.

The subnet mask of 255.255.255.192 corresponds to a /26 prefix, which means that the first 26 bits of the address define the network portion, and the remaining 6 bits are used for host addresses. Each /26 subnet can accommodate 64 addresses (2^6), including network and broadcast addresses.

To find the subnet that contains the IP address 192.168.168.188:

1. Identify the subnet increments based on the last octet defined by the mask. With a /26, the subnets increment every 64 addresses. The relevant subnets in the last octet are:

• 192.168.168.128 (first address of this subnet)

• 192.168.168.192 (first address of the next subnet)

Thus, the relevant subnet for the IP 192.168.168.188 is 192.168.168.128 to 192.168.168.191.

2. The valid host addresses are